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New Travelling Wave Solution-Based New Riccati Equation for Solving KdV and Modified KdV Equations

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Oct 10, 2020

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Fig. 1

Graphics of the solution equation (14) (u5(x,t)) corresponding to the valuesβ = 3, α = 4, σ = 2, A = 2.65, p = 1, q = 0.9, b0 = 1 and ξ0 = −0.5 (a) 3D plot and (b) contour plot.
Graphics of the solution equation (14) (u5(x,t)) corresponding to the valuesβ = 3, α = 4, σ = 2, A = 2.65, p = 1, q = 0.9, b0 = 1 and ξ0 = −0.5 (a) 3D plot and (b) contour plot.

Fig. 2

Graphics of the solution equation (28) (u14(x,t)) corresponding to the valuesλ = 1.5, m = 3, A = 2.7, p = 1.2, q = 0.9, b0 = 3 and ξ0 = 1.5 (a) 3D plot and (b) contour plot.
Graphics of the solution equation (28) (u14(x,t)) corresponding to the valuesλ = 1.5, m = 3, A = 2.7, p = 1.2, q = 0.9, b0 = 3 and ξ0 = 1.5 (a) 3D plot and (b) contour plot.

Fig. 3

Graphics of the solution equation (28) 



(u1+(x,t))
(u_1^ + (x,t))


 corresponding to the valuesβ = 4, α = 2, σ = 3, A = 2.6, p = 1, q = 0.9 and ξ0 = 0 (a) 3D plot and (b) contour plot.
Graphics of the solution equation (28) (u1+(x,t)) (u_1^ + (x,t)) corresponding to the valuesβ = 4, α = 2, σ = 3, A = 2.6, p = 1, q = 0.9 and ξ0 = 0 (a) 3D plot and (b) contour plot.

Fig. 4

Graphics of the solution equation (34) 



(u7-(x,t))
(u_7^ - (x,t))


 corresponding to the values β = 3, α = 1, σ = 2, A = e, p = 1, q = 1 and ξ0 = 0 (a) 3D plot and (b) contour plot.
Graphics of the solution equation (34) (u7-(x,t)) (u_7^ - (x,t)) corresponding to the values β = 3, α = 1, σ = 2, A = e, p = 1, q = 1 and ξ0 = 0 (a) 3D plot and (b) contour plot.
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